They are produced when the light is reflected between two surfaces - a spherical surface and an adjacent flat surface. In the resultant interference pattern, areas of same brightness are determined by the difference of phases of waves, thickness of the medium material traversed e. These are points that are equidistant from the point of contact of the two surfaces, i. Need a fast expert's response? Place free inquiry.
Calculate the price. Learn more about our help with Assignments: Optics. Comments Assignment Expert. Your comments have been successfully added. However, they need to be checked by the moderator before being published. Choose subject Choose category Related Questions 1. I need to test the resolution of a laser diode imaging system. According to modeling, the resolutio 4. What is the frequency difference of GHz equivalent to at the nm wavelength of Gallium arsenid 5.
What is the average energy in each p 6. Every fringe is the locus of points having equal thickness. Hence the fringes are circular in shape. To calculate the diameter of fringes, assume a plano-convex lens is placed on a plane glass plate as shown in figure say R be the radius of curvature of lens.
The diameter of n th order dark fringe will be. The diameter of n th order bright fringe will be. The diameter of bright ring is proportional to square root of odd natural numbers.
For example the diameter of dark ring is given by. If the monochromatic source is replaced by the white light few coloured rings are seen around dark centre later illumination is seen in the field of view. Class Attendance. Important Questions. MST-I Result. Exam Schedule. MST-I Nov Amita Mourya.
Engineering Physics by Dr. Amita Maurya, Peoples University, Bhopal.
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